Question

What are the factors of x2 − 64?

Prime
(x − 4)(x + 16)
(x − 8)(x − 8)
(x + 8)(x − 8)

Answer 1

Answer:
`(x+8)(x-8)`

Explanation:

The given polynomial :
`x^2-64`

Since both the terms are perfect square.

Rewrite the above equation in the form of difference of two squares:

`x^2-(8)^2`

Using algebraic formula given below:-

`a^2-b^2=(a+b)(a-b)`

`\Rightarrow\ x^2-(8)^2=(x+8)(x-8)`

Hence, the factors of
`x^2-64=(x+8)(x-8)`