Question

What mass of HNO3 (MM=63) is present in 50. mL of a 1.5 M solution?

Answer 1

Molarity = number of moles
---------------------------------
volume of the solution

1.5 = number of moles of HNO3
---------------------------------------
50 x 10^-3

Therefore, number of moles of HNO3 = 50 x 10^-3 x 1.5 = 0.075 moles.

Therefore, mass of HNO3 = moles x molar mass of HNO3
= 0.075 x 63
= 4.725 grams.

Answer 2

Remember that molarity * volume will give you moles. And then using the molar mass, you can find the mass.

1.5 M * 0.050 L = 0.075 moles HNO₃

0.075 moles * (63 grams/1mole) = 4.7 grams HNO₃

We are limited to 2 significant figures because of the molarity.

The mass of HNO₃ is 4.7 grams.