Question

A population of deer is 1,500 and is growing 2% each year. Predict the population after 4 years

Answer 1

the cheap answer is, well, is compounding every year, thus use the compound interest equation


`\bf \qquad \textit{Compounded Amount} \\\\ A=P\left(1+(r)/(n)\right)^(nt) \qquad \begin{cases} A=\textit{current amount}\\ P=\textit{original amount }\to &\$1500\\ r=rate\to 2\%\to (2)/(100)\to &0.02\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, so once} \end{array}\to &1\\ t=years\to &4 \end{cases}`