Question

On the integral of 1 to 9, what is sqrtx in respect to x?

9
∫√x dx
1

(Sorry not sure how else to write it..)

Answer 1

Use the fundamental theorem of calculus and by the way turn x into x^1/2 dx.

Answer 2

`\bf \displaystyle \int\limits_(1)^(9)\ √(x)\cdot dx \iff\displaystyle \int\limits_(1)^(9)\ x^{(1)/(2)}\cdot dx \\\\\\ \cfrac{x^{(1)/(2)+1}}{(1)/(2)+1}\implies \cfrac{x^{(3)/(2)}}{(3)/(2)}\implies \left. \cfrac{2√(x^3)}{3} \right]_(1)^(9)`

you tell us