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Logarithm 2. The alkalinity of a fluid (pH) can be modeled in terms of its hydrogen ion concentration (H^+,measured in moles/liter) of the fluid using the model shown below:pH = -log(H^+)A lab technician finds that a sample of fluid has a pH of 4.5. What is the hydrogen ion concentration of the fluid?

Logarithm 2. The alkalinity of a fluid (pH) can be modeled in terms of its hydrogen-example-1
User Mackcmillion
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1 Answer

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28 votes

ok. We are given the following equation:


ph=-\log (H)

Where:


\begin{gathered} P=\text{ alkalinity} \\ H=\text{ hydrogen ion concentration} \end{gathered}

Since we are asked to determine "H" we will solve for "H" in the equation. To do that we will first multiply both sides by -1:


-ph=\log (H)

Now, we will use the following property of logarithms:


\log _aB=c\rightarrow B=a^c

Applying the property and having into account that:


\log (H)=\log _(10)(H)

We get:


10^(-pH)=H

Now we substitute the given value of "pH = 4.5":


10^(-4.5)=H

Solving the operation:


0.000032=H

Therefore, the hydrogen ion concentration of the fluid is 0.000032

User Karena
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