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calculate the concentration of sodium ions made by diluting 45.0 mL of a 0.748 M solution of sodium sulfide to a total volume of 250.0 mL
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calculate the concentration of sodium ions made by diluting 45.0 mL of a 0.748 M solution of sodium sulfide to a total volume of 250.0 mL

User Kracejic
by
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2 Answers

2 votes
C1V1= C2V2
use this formula C1= 0.748 M
V1= 45.0 mL change to L
V2= 250.0 mL again change to L
C2= ?
User Paulcam
by
7.0k points
2 votes
Use the formula M1V1 = M2V2
45(0.748) = 250(M2)
33.66 = 250(M2)
M2 = 0.135 M
User Eli Jayson
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9.2k points
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