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Solve 2x2 + 12x − 14 = 0 by completing the square. 2(x + 6)2 = 26; x = −6 + √13, x = −6 − √13 2(x + 6)2 = 20; x = −6 + √20, x = −6 − √20 2(x + 3)2 = 32; x = 1, x = −7 2(x + 3) 2 = 32; x = 13, x = 19 What
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Solve 2x2 + 12x − 14 = 0 by completing the square.

2(x + 6)2 = 26; x = −6 + √13, x = −6 − √13
2(x + 6)2 = 20; x = −6 + √20, x = −6 − √20


2(x + 3)2 = 32; x = 1, x = −7 2(x + 3)
2 = 32; x = 13, x = 19

What do I do now? Can someone help me please? :/
User Ammar Bukhari
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According to my calculations, the answer would be 2(x + 3)2 = 32; x = 1, x = −7.

(hope this helps)
User Leiby
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