Question

James is playing an arcade game with tokens. In the firstgame, he hits the jackpot and doubles the number oftokens that he has. In the second game, James wins 12more tokens. In his third and final game, he loses 4tokens. James now has 170 tokens. How many tokensdid he have before he started playing the game?

Answer 1

Let's call X the number of tokens than he has before start playing the game.

In the first game, he hits the jackpot and doubles the number of tokens that he has. So, after the first game, he has a double of X or 2X.

In the second game, James wins 12 more tokens. So, he has now 2X + 12 tokens.

In his third and final game, he loses 4 tokens. So, he has 2X + 12 - 4 tokens.

Now he has 170 tokens. It means that:

2X + 12 - 4 = 170

Therefore solving for X, we get:

`\begin{gathered} 2X+12-4=170 \\ 2X+8=170 \\ 2X+8-8=170-8 \\ 2X=162 \\ (2X)/(2)=(162)/(2) \\ X=81 \end{gathered}`

Answer: 81 tokens