Problem
In the figure below, m<1 =(15x - 5) and m<3 =(10x + 35)Find x = and m<2
Solution
For this case we can see that m<1 = m<3 so we have:
15x -5 = 10x +35
5x= 40
x= 8
Then we know that total circle measures 360º so we can do this:
115 + 115 + 2m <2 = 360
And solving for m<2 we got:
m <2 = (360-115-115)/2 =
65º