Question

6. Sasha traveled 650 meters north in 55 seconds and then traveled 350 meters east in 35 seconds. The magnitude ofSasha's average velocity was most nearly(a) 5.9 m/s(b) 8.2 m/s(c) 9.6 m/s(d) 11 m/s

Answer 1

(b) 8.2 m/s

Explanation:

To calculate the velocity value, first we must calculate the resulting distance between 650 and 350 meters, that is, from the point (650, 350) and the origin (0,0).

We calculate it as follows:

`d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}`

Replacing:

`\begin{gathered} d=\sqrt[]{\mleft(0-650\mright)^2+\mleft(0-350\mright)^2} \\ d=738.2 \end{gathered}`

We know that velocity is the distance in a given time, therefore we divide the resulting distance by the sum of both given times, like this

`\begin{gathered} v=(738.2)/(55+35) \\ v=8.2 \end{gathered}`

The velocity is 8.2 meters per second