Question

There are 3 sets of balls numbered 1 through 12 placed in a bowl. if balls are randomly chosen without replacement, find the probability that the balls have the same number. Express your answer as fraction.

Answer 1

Step-by-step explanation:

Given the 3 sets of balls numbered 1 through 12, the total number of balls:

12 * 3 = 36 balls.

The balls have the same numbers if they are on the:

1, 1, 1

2, 2, 2

3, 3, 3

and so on.

This can happen 12 times.

Finally, the probabiliticy we seek is

12/(36C3)

36C3 = 36!/(36 - 34)!3!/(36C3)

36C3 = 36!/(36 - 34)!3!

12