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The radius r of a circle can be written as a function of the area A with the following equation: What is the domain of this function? Explain why it makes sense in this context.

User Alonso
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[0,infinity) because you can not take the radius of a negative mumber.
User Mda
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Answer:

Hence, the domain of the function is:

[0,∞)

Explanation:

We know that area of circle is given by the function:


A=\pi r^2

The radius r of a circle can be written as a function of the area A with the following equation:

Now we can represent r in terms of A as:


r^2=(A)/(\pi)\\\\r=\sqrt{(A)/(\pi)}

Now as we know that for the square root term to exist:


\sqrt{(A)/(\pi)}\geq0

i.e.
A\geq0

A=0 represents a point circle since it's area is zero.

Hence, the domain of the function is:

[0,∞)

User Deept Raghav
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