Width of path is
3
meters.
Step-by-step explanation:
The dimensions of pool are
16
meters and
18
meters
as it is surrounded by a path of uniform width, let the width be
x
meters and
the dimensions of the pool and the path combined will be
16
+
2
x
and
18
+
2
x
and as area is
528
m
2
, the equation is
(
16
+
2
x
)
(
18
+
2
x
)
=
528
or
288
+
32
x
+
36
x
+
4
x
2
=
528
i.e.
4
x
2
+
68
x
−
240
=
0
and dividing by
4
x
2
+
17
x
−
60
=
0
i.e.
(
x
+
20
)
(
x
−
3
)
=
0
i.e.
x
=
−
20
or
x
=
3