Question

Answer if you know the answer

show all work

solve for x


`(3^(2x-1))(3^2)=(3x^(2+x))(3^x)`

Answer 1

`3^(2x-1)3^2=3^(2+x)3^x`

`3^(2x-1+2)=3^(2+x+x)`

`3^(2x+1)=3^(2x+2)`

Because the bases are identical, so must be the exponents, meaning you have


`2x+1=2x+2`

but this has no solution.