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A yellow lamp emits light with a wavelength of 6.00 · 10-7 m. Use Planck's equation to calculate the energy of a single photon with the given wavelength.

E = _____ J

A. 1.33 x 10-48

B. 3.32 x 10-49

C. 1.19 x 10-31

D. 3.32 x 10-19

1 Answer

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Answer:

Energy of a single photon with the given wavelength is
E=3.32* 10^(-19)\ J

Step-by-step explanation:

It is given that,

The wavelength of yellow light,
\lambda=6* 10^(-7)\ m

The equation that gives the relationship between the energy and the frequency of the wave is called Plank's equation. Mathematically, it can be written as :


E=h\\u

where
\\u is the frequency of the wave and
\\u=(c)/(\lambda)

h is Planck's constant

So,
E=(hc)/(\lambda)


E=(6.62* 10^(-34)\ J-s* 3* 10^8\ m/s)/(6* 10^(-7)\ m)


E=3.32* 10^(-19)\ J

So, the energy of photon is
E=3.32* 10^(-19)\ J

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