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32 votes
32 votes
Solve sin2x-sin4x +sin6x=0

User Chris Perkins
by
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1 Answer

10 votes
10 votes

Remember that


\sin 2\theta=2\sin \theta\cos \theta

Therefore,


\begin{gathered} \sin 2x-\sin 4x+\sin 6x=0 \\ \Rightarrow2\sin x\cos x-2\sin 2x\cos 2x+2\sin 3x\cos 3x=0 \end{gathered}

Then,


undefined

User Fullstacklife
by
3.2k points