Question

Sergio has two similar cylindrical pots, Pot A and Pot B. The radius of Pot A is 24 inches, and the radius of Pot B is 6 inches. What is the ratio of the volume of Pot A to the volume of Pot B?

PLEASE SOMEONE HELP ITS URGENT THANK YOU!!

Answer 1

The ratio of the volume of Pot A to the volume of Pot B is 64.

Step-by-step explanation:

To find the ratio of the volume of Pot A to the volume of Pot B, we can use the formula for the volume of a cylinder, which is πr^2h. Since the pots are similar, their heights will be in the same ratio as their radii.

The volume of Pot A is given by π(24^2)h, and the volume of Pot B is given by π(6^2)h. Let's assume the height of Pot A is h, so the height of Pot B will be h/4. Plugging the values into the formulas, we get:

Volume of Pot A = π(24^2)h = 576πh

Volume of Pot B = π(6^2)(h/4) = 9πh

Now we can find the ratio of the volumes by dividing the volume of Pot A by the volume of Pot B:

(Volume of Pot A) / (Volume of Pot B) = (576πh) / (9πh) = 64

Therefore, the ratio of the volume of Pot A to the volume of Pot B is 64.

Answer 2

A/B or 24/6 (24:6)


4:1 or just 4.