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3 votes
Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth.

User Mark Nold
by
7.4k points

2 Answers

1 vote
using distance formula =√(5-3)sq+(1-4)sq
=√4+9
=√13
User Ryan Daulton
by
8.5k points
2 votes

Answer:

3.6 units

Explanation:

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is:


PQ=\sqrt{(y_(2)-y_(1))^2+(x_(2)-x_(1))^2 }


PQ=√((4-1)^2+(3-5)^2)


PQ=√((3)^2+(-2)^2)


PQ=√(9+4)


PQ=√(13)


PQ=3.6 units

Thus, the distance between the given two points is 3.6 units.

User Lesha Ogonkov
by
8.9k points

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