Question

Factor completely. M^4 - n^4

Answer 1

(m^2+n^2)(m+n)(m-n)

Explanation:

Answer 2

`(M^2+n^2)(M-n)(M+n)`

Explanation:

This is a difference of squares polynomial of the form
`a^2-b^2=(a+b)(a-b)`. Since
`M^4` and
`n^4` are both perfect squares then take the square root of each so a=
`M^2` and b=
`n^2`.

`(M^2+n^2)(M^2-n^2)`

We have another difference of squares and repeat the process.

`(M^2+n^2)(M-n)(M+n)`

Notice that a sum of squares is not factorable.