Question

What is the minimum Brianna can lost the house to accommodate both of these requirements, round the the nearest hundred dollars

Answer 1

We are given that Brianna needs to receive $199300 and that she also needs to allow for a 3 percent commission. Let "x" be the amount Brianna needs to sell her house. We need to subtract from this amount the 3% commission. To do that we will use the following relationship:

`x-(3)/(100)x=199300`

Now, we solve for "x" first by adding the fractions using the following model:

`a+(b)/(c)=(ac+b)/(c)`

Therefore, we will multiply the 100 from the denominator by "x" and subtract 3 from the result, like this:

`(100x-3x)/(100)=199300`

Solving the operations we get:

`(97x)/(100)=199300`

Now we multiply both sides by 100:

`97x=19930000`

Now we divide both sides by 97:

`x=(19930000)/(97)=205463.92`

Therefore, the amount is $205463.92. Since we are told to round to the nearest hundred dollars we round the answer to $205500.