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Find two consecutive whole numbers such that the sum of their squares is 421

Find two consecutive whole numbers such that the sum of their squares is 421
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Find two consecutive whole numbers such that the sum of their squares is 421

User Christiaan Janssen
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The equation you would need to solve is x^2+(x+1)^2=421. I'm not at a college level though so i don't know how to.

Give me feedback if this helped!
User Clark Wright
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