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The equation for the circle is: x2+y2−12x+6y−19=0 What is the center of the circle? A. (-6, 3) B. (12, -6) C. (6, -3) D. (-12, 6)
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The equation for the circle is:

x2+y2−12x+6y−19=0



What is the center of the circle?

A. (-6, 3)
B. (12, -6)
C. (6, -3)
D. (-12, 6)

User Weaver
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4 votes
 I would say d is the best one
User Whostolebenfrog
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He equation for the circle is: x2+y2−12x+6y−19=0 . What is the center of the circle?
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