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The equation for the circle is:

X^2 + y^2 - 12x + 6y - 19 = 0

What is the center of the circle?

A. (-6, 3)
B. (12, -6)
C. (6, -3)
D. (-12, 6)

User TiagoDias
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7.0k points

1 Answer

4 votes

Answer:

C. (6, -3)

Explanation:

The x- and y-coordinates are the opposite of half the corresponding linear term coefficient:

-(-12, 6)/2 = (6, -3)

This can be confirmed using a graphing calculator.

The equation for the circle is: X^2 + y^2 - 12x + 6y - 19 = 0 What is the center of-example-1
User Robin Fisher
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