Question

The equation for the circle is:

X^2 + y^2 - 12x + 6y - 19 = 0

What is the center of the circle?

A. (-6, 3)
B. (12, -6)
C. (6, -3)
D. (-12, 6)

Answer 1

C. (6, -3)

Explanation:

The x- and y-coordinates are the opposite of half the corresponding linear term coefficient:

-(-12, 6)/2 = (6, -3)

This can be confirmed using a graphing calculator.