The equation for the circle is: X^2 + y^2 - 12x + 6y - 19 = 0 What is the center of the circle? A. (-6, 3) B. (12, -6) C. (6, -3) D. (-12, 6)

Question

asked Oct 25, 2018 228k views

1 Answer

Robin Fisher · Answer 1 · 2018-10-30T00:23:23+0000

Answer:

C. (6, -3)

Explanation:

The x- and y-coordinates are the opposite of half the corresponding linear term coefficient:

-(-12, 6)/2 = (6, -3)

This can be confirmed using a graphing calculator.