Find the 9th term of the geometric sequence whose common ratio is 1/3 and whose first term is 6.

Leo Orientis asked Aug 11, 2023

120,158 views

10 votes

Leo Orientis asked Aug 11, 2023

2.7k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

22 votes

Given: the geometric sequence whose common ratio is 1/3 and whose first term is 6.

Find: 9th term of the geometric sequence

Explanation:

$\begin{gathered} a_n=a_1(r)^(n-1) \\ a_9=6((1)/(3))^(9-1) \\ a_9=6((1)/(3))^8 \end{gathered}$

Final answer: the required answer is

Pierre Nortje answered Aug 15, 2023

3.0k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers