Question

A train approaching a crossing changes speed from 25 m/s to 10 m/s in 240 s. How can the train's acceleration be described?

Answer 1

the trains acceleration is deceleration.

Answer 2

The acceleration described by the train is 0.0625 m/s² and is decelerating.

Step-by-step explanation:

It is given that,

Initial speed if the train, u = 25 m/s

Final speed of the train, v = 10 m/s

Time taken, t = 240 s

We have to find the acceleration of the train. It is equal to the rate of change of speed. It can be calculated suing first equation of motion as :

`a=(v-u)/(t)`

`a=(10\ m/s-25\ m/s)/(240\ s)`

a = -0.0625 m/s²

Hence, the acceleration described by the train is 0.0625 m/s² and the train is decelerating.