Question

What values of b satisfy 4(3b+2)^2=64

Answer 1

Answer: b=2/3 and b=-2

Explanation:

Answer 2

`4(3b+2)^2=64`

solve for b:

take the square root of both sides:

`\begin{gathered} \sqrt[]{4(3b+2)^2}=\sqrt[]{64} \\ \sqrt[]{4}\cdot\sqrt[]{(3b+2)^2}=\pm8 \\ 2(3b+2)=\pm8 \\ 6b+4=\pm8 \\ so\colon \\ b=(\pm8-4)/(6) \end{gathered}`

therefore:

`\begin{gathered} b=(2)/(3) \\ or \\ b=-2 \end{gathered}`