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Find the mean absolute deviation of 5,9,7,0,3,5,5

1 Answer

6 votes

Answer: 1.92

Explanation:

Formula to find the mean absolute deviation:


MAD =\sum^(n=i)_(n=1)\frac{|x_i-\overlien{x}|}{n}

, where
\overline{x}= mean ,
x_i's = data values, n= number of data values.

Given data: 5,9,7,0,3,5,5

n= 7

Mean:


\overline{x}=(5+9+7+0+3+5+5)/(7)\\\\=(34)/(7)

MAD =
\frac +{7}


=(\frac17+(29)/(7)+(15)/(7)+(34)/(7)+(13)/(7)+\frac17+\frac17)/(7)\\\\=((94)/(7))/(7)\\\\=(94)/(49)\approx1.92

Hence, the mean absolute deviation of 5,9,7,0,3,5,5 is 1.92(approx)

User Amay Kulkarni
by
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