Question

Find the equation of a line which passes through the point (3, –4) and has a slope of –3. Put your final answer in standard form

Answer 1

Answer: 3x+y=5

Explanation:

Equation of a line that has slope(m) and passes through point (a,b) is given by :-

`(y-b)=m(x-a)`

Given: Point = (3,-4)

Slope =-3

Then, the equation of the required line:

`(y-(-4))=-3(x-3)\\\\\Rightarrow\ (y+4)=-3(x-3)\\\\\Rightarrow\ y+4=-3x+9\\\\\Rightarrow\ 3x+y=9-4\\\\\Rightarrow\ 3x+y=5\ \ \ \ [\text{Standard form: Ax+By=C}]`

Hence, required equation: 3x+y=5