Al(NO₃)₃ (aq) + 3NaOH(aq) --> Al(OH)₃ (s) + 3NaNO₃ (aq)
Keep in mind that any compound that contains nitrate will be soluble. Al(OH)₃ is insoluble. If the group 1A or 2A metals were with OH⁻, then it would have been soluble.
The precipitate would be aluminum hydroxide.
Let's now find the net ionic equation
Al(NO₃)₃ (aq) + 3NaOH(aq) --> Al(OH)₃ (s) + 3NaNO₃ (aq)
Al³⁺(aq) + 3NO₃⁻(aq) + 3Na⁺(aq) + 3OH⁻(aq) --> Al(OH)₃(s) + 3Na⁺(aq) + 3NO₃⁻(aq)
That is the molecular equation
The net ionic equation would be:
Al³⁺(aq) + 3OH⁻(aq) --> Al(OH)₃ (s)