Question

Please help me find WZ and UZ. (Show work)

Answer 1

since those two triangles are similar by AA
then use proportions to get "x"

thus
`\bf \cfrac{x+4}{16}=\cfrac{x-08}{WU}` hmmm wait just a second? what the dickens is WU anyway?

well, let's take a look at the triangle on the right-side
is a right-triangle, has a 90° angle

so, just use the pythagorean theorem to get WU


`\bf c^2=a^2+b^2\implies √(c^2-a^2)=b\qquad \begin{cases} c=WY\\ a=UY\\ b=WU \end{cases}\\\\ -----------------------------\\\\ √((WY)^2-(UY)^2)=WU`

which will give you
`\bf \cfrac{x+4}{16}=\cfrac{x-08}{\boxed{√((WY)^2-(UY)^2)}}`

solve for "x"