Question

What is the rate of change of the volume of the cylinder at that instance (in cubic kilometers per second)?

Answer 1

hello your question is incomplete attached below is the complete question

answer : -2400 π

Explanation:

dr/dt = -12 km/s

h = 2.5 km

r = 40 km at some instant

hence the rate of change of Volume of cylinder at that instance

= dv / dt =
`d(\pi r^h ) / dt`

=
`\pi h(d(r^2))/(dt)` =
`-\pi h *2r *dr/dt`

hence ; dv / dt = -2400 π