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What volume of 7.25 mol/L stock solution in needed to make 3.84 L of 8.50 mol/L solution?

User Kiahni
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2 Answers

8 votes

Final answer:

To make a solution with a concentration of 8.50 mol/L using a stock solution with a concentration of 7.25 mol/L, a volume of 4.51 L is needed.

Step-by-step explanation:

To calculate the volume of the stock solution needed to make the desired concentration, we can use the formula:

C1V1 = C2V2

where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the desired solution.

Plugging in the values, we get:

(7.25 mol/L)(V1) = (8.50 mol/L)(3.84 L)

After rearranging the equation, we find that the volume of the stock solution needed is:

V1 = (8.50 mol/L)(3.84 L) / (7.25 mol/L) = 4.51 L

User Edsel
by
3.5k points
5 votes

Answer:

4.50 L

Step-by-step explanation:

First we calculate how many moles are there in 3.84 L of a 8.50 mol/L solution:

  • 3.84 L * 8.50 mol/L = 32.64 mol

Now, keeping in mind that

  • Concentration = Mol / Volume

we can calculate the volume of a 7.25 mol/L solution that would contain 32.64 moles:

  • Volume = Mol / Concentration
  • Volume = 32.64 mol รท 7.25 mol/L
  • Volume = 4.50 L

So we could take 4.50 L of the 7.25 mol/L solution and evaporate the solvent until only 3.84 L remain.

User Ekad
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2.9k points