1 Answer

Tyler Marien · Answer 1 · 2023-09-26T04:42:59+0000

Consider that the area of a sector of a circle is given by:

$A=(\theta)/(360)\pi r^2$

where θ is the angle of the sector and r is the radius.

For θ=40 and r = 8cm, you obtain:

$A=(40)/(360)\pi(8cm)^2=22.34cm^2$

The area of the small sector is about 22.34 cm^2.

Now, for θ=320 and r = 8cm, you obtain:

$A^(\prime)=(320)/(360)\pi(8cm)^2=178.72cm^2$

The area of the small sector is about 178.72 cm^2.

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