Question

Log25x-log5=2

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Answer 1

40

Explanation:

Answer 2

since no base is stated, assume base 10
remember
loga-logb=log(a/b)
also

`log_a(b)=c` translates to
`a^c=b`
and log(a^z)=zlog(a)

log25x-log5=2 means

`log_(10)(25x)-log_(10)(5)=2` translates to

`log_(10)( (25x)/(5) )=2` simplies to

`log_(10)(5x)=2` translates to

`10^2=5x` expands to
100=5x
divide both sides by 5
20=x