Question

The large piston in a hydraulic lift has an area of 2m^2. What force must be applied to the small piston with an area of .2m^2 in order to raise a car that weighs 14,700 Newtons

Answer 1

147,000N

Explanation:

A1= 2m^2

A2= 0.2m^2

F2= 14,700N

Required

F1, the applied force

Applying the formula

F1/A1= F2/A2

substute

F1/2=14700/0.2

2*14700= F1*0.2

29400= F1*0.2

F1= 29400/0.2

F1=147,000N

Hence, the applied force is 147,000N