OK either the equation is

or

Either way it ends up the same because if it is the first equation, I would move the

to the other side of the equation. It would become

.
For my example, I am going with
Square both sides
2x+4=

Then use FOIL to solve the right side
2x+4=

Then combine like terms
2x+4=

Set it equal to 0 and combine like terms

0=x(x-2)
So x=0 and x=2
If it was the other was it would be x=-2
Hope that helps.