We can represent the width as x and the length as x+5. Then we can make the area formula A=(x)*(x+5), plug in 36 for A, and solve for x
36=x^2+5x (distribute)
0=x^2+5x-36
0=(x+9)(x-4)
So x=-9 and 4 but dimensions can't be negative so x=4
So if the width is 4, then the length is 9 (4+5)
Hope this helps :)