Question

You have 0.5 L of air at 203 k in an expandable container at constant pressure. You heat the container to 273 k. What is the volume of the air?

A. 0.25 L
B. 1.5 L
C. 0.67 L
0.37 L

Answer 1

0.67 L

Step-by-step explanation:

Answer 2

You can use P1V1/T1 = P2V2/T2 but since pressure is constant is becomes V1/T1=V2/T2

V1=0.5 L
T1=203 K
T2=273 K
V2=unknown

0.5L/203 = V2/273
V2= 0.67 L so C

Hope this helps :)