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Could somebody help me?

Could somebody help me?-example-1
User Irieill
by
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1 Answer

7 votes
Solving for a:

2a
x^(4)+
x^(3)-bx+5 = 4
x^(4)+
x^(3)-c
x^(2)+2x+5
Subtract 5 and
x^(3) from both sides:
2a
x^(4)-bx=4
x^(4)-c
x^(2)+2x
Add bx to both sides:
2a
x^(4)=4
x^(4)-c
x^(2)+2x+bx
Divide both sides by 2
x^(4):
a = 4
x^(4)-c
x^(2)+2x+bx/2
x^(4)
Simplify:
a = 4
x^(3)-cx+2+b/2
x^(3)

Solving for b:

Begin by doing the same as for a by subtracting 5 and
x^(3) from both sides. Again add bx to both sides to avoid having to work with negatives. You should now have 2a
x^(4)=4
x^(4)-c
x^(2)+2x+bx.
Subtract 4
x^(4) and 2x from both sides as well as adding c
x^(2) to both sides:
2a
x^(4)-4
x^(4)+c
x^(2)-2x=bx
Divide both sides by x:
b = 2a
x^(4)-4
x^(4)+c
x^(2)-2x/x
Simplify:
b = 2a
x^(3)-4
x^(3)+cx-2

Solve for c:

Begin again by subtracting 5 and
x^(3) from both sides. Next add c
x^(2) to both sides to again avoid working with negatives:
2a
x^(4)-bx+c
x^(2)=4
x^(4)+2x
Subtract 2a
x^(4) and add bx to both sides:
c
x^(2)=4
x^(4)+2x-2a
x^(4)+bx
Divide both sides by
x^(2):
c = 4
x^(4)+2x-2a
x^(4)+bx/
x^(2)
Simplify:
c = 4
x^(3)+2-2a
x^(3)+b/x
User Josean
by
7.3k points

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