Question

Could somebody help me?

Answer 1

Solving for a:

2a
`x^(4)`+
`x^(3)`-bx+5 = 4
`x^(4)`+
`x^(3)`-c
`x^(2)`+2x+5
Subtract 5 and
`x^(3)` from both sides:
2a
`x^(4)`-bx=4
`x^(4)`-c
`x^(2)`+2x
Add bx to both sides:
2a
`x^(4)`=4
`x^(4)`-c
`x^(2)`+2x+bx
Divide both sides by 2
`x^(4)`:
a = 4
`x^(4)`-c
`x^(2)`+2x+bx/2
`x^(4)`
Simplify:
a = 4
`x^(3)`-cx+2+b/2
`x^(3)`

Solving for b:

Begin by doing the same as for a by subtracting 5 and
`x^(3)` from both sides. Again add bx to both sides to avoid having to work with negatives. You should now have 2a
`x^(4)`=4
`x^(4)`-c
`x^(2)`+2x+bx.
Subtract 4
`x^(4)` and 2x from both sides as well as adding c
`x^(2)` to both sides:
2a
`x^(4)`-4
`x^(4)`+c
`x^(2)`-2x=bx
Divide both sides by x:
b = 2a
`x^(4)`-4
`x^(4)`+c
`x^(2)`-2x/x
Simplify:
b = 2a
`x^(3)`-4
`x^(3)`+cx-2

Solve for c:

Begin again by subtracting 5 and
`x^(3)` from both sides. Next add c
`x^(2)` to both sides to again avoid working with negatives:
2a
`x^(4)`-bx+c
`x^(2)`=4
`x^(4)`+2x
Subtract 2a
`x^(4)` and add bx to both sides:
c
`x^(2)`=4
`x^(4)`+2x-2a
`x^(4)`+bx
Divide both sides by
`x^(2)`:
c = 4
`x^(4)`+2x-2a
`x^(4)`+bx/
`x^(2)`
Simplify:
c = 4
`x^(3)`+2-2a
`x^(3)`+b/x