Answer:
1 baseball cost $4
1 ping pong cost $1.5
Explanation:
let the cost of baseball be b and the cost of ping pong be p
10 baseballs = 10b
4 ping pong = 4p
Adding both gives total $46
10b + 4p = 46 •••••••••(i)
baseball costs 1 dollar more than 2 ping pong
b = 2p + 1 •••••••(ii)
Substitute ii into i
10(2p + 1) + 4p = 46
20p + 10 + 4p = 46
24p = 46-10
24p = 36
p = 36/24
p = $1.5
b = 2p + 1
b = 2(1.5) + 1
b = 3 + 1 = $4