426,808 views
11 votes
11 votes
A building cast a shadow that is 64 feet long at the same time a woman standing nearby who is 5 feet tall cast a shadow that is 4 feet long how tall is the building in feet

User Ron Rebennack
by
2.9k points

1 Answer

13 votes
13 votes

Step-by-step explanation

To derive the answer to the question, we would have to draw some diagrams.

The above diagram shows the triangle formed from the height of the building and the shadow

We will also draw another triangle

The above diagram shows the triangle formed from the height of the woman and the shadow

This is simply a case of similar triangles.

Therefore we can find the height by taking the ratio of the sides.


\begin{gathered} \frac{Height\text{ of building}}{Height\text{ of woman}}=\frac{shadow\text{ of building}}{\text{shadow of woman}} \\ (64)/(4)=(h)/(5) \\ Cross\text{ multiply} \\ 4h=64*5 \\ h=(64*5)/(4) \\ h=16*5 \\ h=\text{ 80} \end{gathered}

Therefore, the height of the building is 80 feet

A building cast a shadow that is 64 feet long at the same time a woman standing nearby-example-1
A building cast a shadow that is 64 feet long at the same time a woman standing nearby-example-2
User Chuk
by
3.1k points