Options :
Determine whether the equation has the form a = a, and if it does, the equation has infinitely many solutions. Determine whether the equation has the form a = b, and if it does, the equation has no solution. Determine whether the equation has the form x = a, and if it does, the equation has one solution. Determine whether the equation has the form x = 0, and if it does, the equation has no solution.
Answer:
Determine whether the equation has the form x = a
Explanation:
Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3
-3(x + 1) + 3x = - 3(x - 1) + 3
If the equation has the form x =a, where a is the unknown and a is the value of the unknown 'x'
Expanding :
-3x - 3 + 3x = - 3x + 3 + 3
-3x + 3x -3 = - 3x + 6
-3 = - 3x + 6
-3 - 6 = - 3x
-9 = - 3x
x = 9/3
x = 3