Question

The first order reaction,so2cl2 to so2+cl2,has a half life of 8.75 hours at 593k.How long will it take for the concentration of so2cl2 to fall to 12.5% of its initial value? 6.24hours 26.2hours 16.2hours 22.6hours

Answer 1

Answer: The time after which the concentration of
`SO_2Cl_2` fall to 12.5% of its initial value is 26.2 hours

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

`t=(2.303)/(k)\log(a)/(a-x)`

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant = 100

a - x = amount left after decay process = 12.5

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

`t_{(1)/(2)}=(0.693)/(k)`

`k=(0.693)/(8.75hour)=0.0792hour^(-1)`

b) for concentration to fall to 12.5 % of initial value

`t=(2.303)/(0.0792)\log(100)/(12.5)`

`t=26.2hours`

The time after which the concentration of
`SO_2Cl_2` fall to 12.5% of its initial value is 26.2 hours