Question

Two functions, A and B, are described as follows:

Function A
y = 8x + 3

Function B
The rate of change is 1 and the y-intercept is 4.

How much more is the rate of change of function A than the rate of change of function B?

1
7
8
9

Answer 1

7

Explanation:

The standard model equation here is

y = mx+b

Now,

x and y are the variables

b is y-intercept, it means it is the value of y-coordinate on y axis where this line intercepts on y-axis

m = slope or rate of change or angle ∅ this line making with x -axis.

now arrange function A according to standard model equation

y = (8)x + 3

now, by comparison of standard and function A

m(A) = 8 and b(A) = 3

For function B

it is given that rate of change or slope is 1 and y-intercept is 4

so for function b

m(B) = 1 and b(B) = 4

Now question is about how much slope of function A is more than slope of function B

m(A)-m(B) = 8-1 = 7

So answer is 7.

Answer 2

`7`

Explanation:

we have

`y=8x+3` -------> equation A

In the equation A the rate of change is equal to the slope m

`m=8`

In the equation B

we have

`m=1` ------> rate of change

`b=4`

The equation B is equal to

`y=mx+b`

substitute

`y=x+4`

Find the difference of the rate of change of function A minus the rate of change of function B

`8-1=7`