Question

Find an equation for the line that passes through the points (-4, -2) and (2,6).

Answer 1

y=4/3x+10/3

Explanation:

m=(y2-y1)/(x2-x1)

m=(6-(-2))/(2-(-4))

m=(6+2)/(2+4)

m=8/6

m=4/3

y-y1=m(x-x1)

y-(-2)=4/3(x-(-4))

y+2=4/3(x+4)

y=4/3x+16/3-2

y=4/3x+16/3-6/3

y=4/3x+10/3