Question

The sum of three numbers is 41

The second number is 5 times the first
The third number is 14 less than the second
What is the third number?​

Answer 1

11

Explanation:

let the first number be n , then the second number is 5n and

the third number is 5n - 14

Sum the numbers and equate to 41

n + 5n + 5n - 14 = 41

11n - 14 = 41 ( add 14 to both sides )

11n = 55 ( divide both sides by 11 )

n = 5

Thus

first number = 5

second number = 5n = 5 × 5 = 25

third number = 5n - 14 = 5(5) - 14 = 25 - 14 = 11