Question

A survey asked people whether their pets are picky eaters. For theseresults, are being a picky eater and being a dog independent ordependent events? Justify your answer.PickyNot picky TotalCats111425Dogs61925Total173350A. Independent;P(picky) = 34%P(doglpicky) = 35%Since these probabilities are nearly equal, the events areindependent.B. Dependent;P(picky) = 34%P(pickyldog) = 24%Since these probabilities are not equal, the events aredependent.c. Dependent;P(picky) = 34%P(doglpicky) = 35%Since these probabilities are not equal, the events aredependent

Answer 1

Given:

The data table of the survey of pets is given.

Required:

Find results, are being a picky eater and being a dog with independent or dependent events.

Step-by-step explanation:

The total number of pets = 50

The number of picky eater pets = 17

The probability of an event is given by the formula:

`P=\frac{number\text{ of possible outcomes}}{Total\text{ number of outcomes}}`

The probability of randomly choosing a picky eater is:

`\begin{gathered} P(picky)=(17)/(50) \\ P(picky)=0.34 \\ P(picky)=34\% \end{gathered}`

The total number of dogs = 25

The number of picky eater cats = 6

The probability of a picky eater dog

We notice that both results are different. The fact that the pet selected is a dog changes the probability of P(picky).

This means the events are dependent.

Final Answer:

Option B is the correct answer.