Question

Factor completely 3a4y3 − 12a3y2 + 6a2y.

3(a4y3 − 4a3y2 + 2a2y)
3a2y(a2y2 − 4ay + 2)
3y(a4y2 − 4a3y + 2a2)
Prime

Answer 1

3a4y3 − 12a3y2 + 6a2y
=3a^2y (a^2y^2 - 4ay + 2)

answer is 3a^2y (a^2y^2 - 4ay + 2) (second choice)

Answer 2

The answer is
`3a^2y(a^2y^2-4ay+2)`

Explanation:

Given the expression
`3a^4y^3-12a^3y^2+6a^2y`

We have to factor the above expression.

`3a^4y^3-12a^3y^2+6a^2y`

Taking
`3a^2y` common from each term, we get

⇒
`3a^2y(a^2y^2-4ay+2)`

Hence, the correct option is second.