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One number is 5 more than another. The difference between their squares is 95. What are the numbers>

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let's say the numbers are "a" and "b"

let's say "b" is the bigger one, and thus is 5 more than "a", or a + 5

so b = a + 5

their difference of their squares is 95, thus
\bf b^2-a^2 =95

thus
\bf \begin{cases} b=a+5\\\\ b^2-a^2=95\\ ----------\\ (a+5)^2-a^2=95 \end{cases}

solve for "a"

what's b? well, b = a + 5
User WildBill
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