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What is the relationship between segment ED and segment AC?

User John Ruiz
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D midpoint of EC -----------------> FD parallel to AC and FD=AC/2=14/2=7
2-EB=EA E midpoint of AB
DB=DC D midpoint BC ...............> ED=AC/2=2
3-T midpoint of SR
U midpoint of QR ---------> TU = QS/2
QS=2 TU = 4.4
4- The same steps SR=2 UV=9
5-N midpoint of KM
O midpoint of ML
* NO parallel to Kl
User Kazutaka
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